Optimal. Leaf size=137 \[ \frac{\tan (c+d x) (3 a A+2 a C+2 b B)}{3 d}+\frac{(4 a B+4 A b+3 b C) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{\tan (c+d x) \sec (c+d x) (4 a B+4 A b+3 b C)}{8 d}+\frac{(a C+b B) \tan (c+d x) \sec ^2(c+d x)}{3 d}+\frac{b C \tan (c+d x) \sec ^3(c+d x)}{4 d} \]
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Rubi [A] time = 0.204339, antiderivative size = 137, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 39, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.18, Rules used = {4076, 4047, 3768, 3770, 4046, 3767, 8} \[ \frac{\tan (c+d x) (3 a A+2 a C+2 b B)}{3 d}+\frac{(4 a B+4 A b+3 b C) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{\tan (c+d x) \sec (c+d x) (4 a B+4 A b+3 b C)}{8 d}+\frac{(a C+b B) \tan (c+d x) \sec ^2(c+d x)}{3 d}+\frac{b C \tan (c+d x) \sec ^3(c+d x)}{4 d} \]
Antiderivative was successfully verified.
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Rule 4076
Rule 4047
Rule 3768
Rule 3770
Rule 4046
Rule 3767
Rule 8
Rubi steps
\begin{align*} \int \sec ^2(c+d x) (a+b \sec (c+d x)) \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\frac{b C \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac{1}{4} \int \sec ^2(c+d x) \left (4 a A+(4 A b+4 a B+3 b C) \sec (c+d x)+4 (b B+a C) \sec ^2(c+d x)\right ) \, dx\\ &=\frac{b C \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac{1}{4} \int \sec ^2(c+d x) \left (4 a A+4 (b B+a C) \sec ^2(c+d x)\right ) \, dx+\frac{1}{4} (4 A b+4 a B+3 b C) \int \sec ^3(c+d x) \, dx\\ &=\frac{(4 A b+4 a B+3 b C) \sec (c+d x) \tan (c+d x)}{8 d}+\frac{(b B+a C) \sec ^2(c+d x) \tan (c+d x)}{3 d}+\frac{b C \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac{1}{3} (3 a A+2 b B+2 a C) \int \sec ^2(c+d x) \, dx+\frac{1}{8} (4 A b+4 a B+3 b C) \int \sec (c+d x) \, dx\\ &=\frac{(4 A b+4 a B+3 b C) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{(4 A b+4 a B+3 b C) \sec (c+d x) \tan (c+d x)}{8 d}+\frac{(b B+a C) \sec ^2(c+d x) \tan (c+d x)}{3 d}+\frac{b C \sec ^3(c+d x) \tan (c+d x)}{4 d}-\frac{(3 a A+2 b B+2 a C) \operatorname{Subst}(\int 1 \, dx,x,-\tan (c+d x))}{3 d}\\ &=\frac{(4 A b+4 a B+3 b C) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{(3 a A+2 b B+2 a C) \tan (c+d x)}{3 d}+\frac{(4 A b+4 a B+3 b C) \sec (c+d x) \tan (c+d x)}{8 d}+\frac{(b B+a C) \sec ^2(c+d x) \tan (c+d x)}{3 d}+\frac{b C \sec ^3(c+d x) \tan (c+d x)}{4 d}\\ \end{align*}
Mathematica [A] time = 0.664224, size = 100, normalized size = 0.73 \[ \frac{3 (4 a B+4 A b+3 b C) \tanh ^{-1}(\sin (c+d x))+\tan (c+d x) \left (8 \left (3 a (A+C)+(a C+b B) \tan ^2(c+d x)+3 b B\right )+3 \sec (c+d x) (4 a B+4 A b+3 b C)+6 b C \sec ^3(c+d x)\right )}{24 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.041, size = 223, normalized size = 1.6 \begin{align*}{\frac{Aa\tan \left ( dx+c \right ) }{d}}+{\frac{B\sec \left ( dx+c \right ) a\tan \left ( dx+c \right ) }{2\,d}}+{\frac{Ba\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}}+{\frac{2\,aC\tan \left ( dx+c \right ) }{3\,d}}+{\frac{C \left ( \sec \left ( dx+c \right ) \right ) ^{2}a\tan \left ( dx+c \right ) }{3\,d}}+{\frac{A\sec \left ( dx+c \right ) b\tan \left ( dx+c \right ) }{2\,d}}+{\frac{Ab\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}}+{\frac{2\,Bb\tan \left ( dx+c \right ) }{3\,d}}+{\frac{Bb\tan \left ( dx+c \right ) \left ( \sec \left ( dx+c \right ) \right ) ^{2}}{3\,d}}+{\frac{C \left ( \sec \left ( dx+c \right ) \right ) ^{3}b\tan \left ( dx+c \right ) }{4\,d}}+{\frac{3\,Cb\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{8\,d}}+{\frac{3\,Cb\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{8\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.0246, size = 294, normalized size = 2.15 \begin{align*} \frac{16 \,{\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} C a + 16 \,{\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} B b - 3 \, C b{\left (\frac{2 \,{\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 12 \, B a{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 12 \, A b{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 48 \, A a \tan \left (d x + c\right )}{48 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.534688, size = 400, normalized size = 2.92 \begin{align*} \frac{3 \,{\left (4 \, B a +{\left (4 \, A + 3 \, C\right )} b\right )} \cos \left (d x + c\right )^{4} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \,{\left (4 \, B a +{\left (4 \, A + 3 \, C\right )} b\right )} \cos \left (d x + c\right )^{4} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (8 \,{\left ({\left (3 \, A + 2 \, C\right )} a + 2 \, B b\right )} \cos \left (d x + c\right )^{3} + 3 \,{\left (4 \, B a +{\left (4 \, A + 3 \, C\right )} b\right )} \cos \left (d x + c\right )^{2} + 6 \, C b + 8 \,{\left (C a + B b\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{48 \, d \cos \left (d x + c\right )^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (a + b \sec{\left (c + d x \right )}\right ) \left (A + B \sec{\left (c + d x \right )} + C \sec ^{2}{\left (c + d x \right )}\right ) \sec ^{2}{\left (c + d x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.31941, size = 578, normalized size = 4.22 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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